(-2b/a^2)5

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Solution for (-2b/a^2)5 equation: 


D( x )

a^2 = 0

a^2 = 0

a^2 = 0

a^2 = 0

x naleu017Cy do R

x belongs to the empty set

((-2*b)/(a^2))^5 = 0

x belongs to the empty set

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